Fielding candidates in STV elections - The Snow In The Summer or So-So

28May

How many candidates should a party field?

After the Irish election, we're inspired to write an Explainer piece. It's answering a poser posed last month by Doctor Vee: Parties are only fielding as many candidates as they can possibly hope to win. In most cases, this is one. And while STV gives voters more choice on paper, this extra choice has actually made me feel a bit suffocated.

If you don't know what STV is, or how it works, then go back a month, read the links there, learn and understand. Remember, the Irish understand this system.

For the purposes of this example, we're going to use an example constituency of 60,000 people, electing five members from amongst six parties. The parties are as follows:

Hypothetical East, 31 June 2007
AbbreviationPollDetails
FF40%Finé Fare, the cheap shopping party
FG28%Fine Gail, promoting wind farms
Nei15%The Neighbour Party, people next door
SF7%Sin Feyn, spreading fertiliser in cities
G6%Groin, liberalising sex laws
DP4%Democratic Progressives, unlike any similarly-named party.

With five people to be elected, the quota is one-sixth of the vote. FF has two and a half quotas. FG has one full quota, and a spare 11%. Neighbour is 2% short of a full quota. SF, G, DP all have less than half a quota. Eyeballing these figures, we would expect the distribution to be: FF 2, FG 2, Nei 1.

On this basis, we can expect FF and FG to put up at least two candidates. Is it in FF's interest to put up a third candidate? Very probably; things can change between the close of nominations and polling day, otherwise the campaigning would be of no benefit whatsoever. If FF were to poll 45%, and have two candidates, the top of the poll might look like this:

Hypothetical East, 31 June 2007 - Quota 10,000
PartyCandidateVoteResult
FFMorrison13,758ELECTED
FFBudgen13,272ELECTED
FGBeaufort8,350

That leaves 7000 FF votes - the best part of a quota - to transfer to the third candidate - but there is no third candidate! These votes might go to FF's preferred partners, but transfers between parties will tend to be even less reliable than transfers within parties. A third candidate might mean that no-one would be elected on the first ballot, but the transfers when the last candidate was excluded would tip both others over the top.

In practice, Irish parties tend to put up one more candidate than they can reasonably expect to win. Let's return to our original model, and put in some numbers.

Hypothetical East, 31 June 2007. Quota - 10,000. Count 1
PartyCandidateVoteResult
FFH. Morrison8000
FFW. Budgen7844
FFM. Marks7747
FGP. Beaufort5786
FGF. Storm5512
FGH. Cane5500
NeiT. Blair4729
NeiG. Brown4654
SFS. M. Tex4360
GI. Chagall3592
DPC. Eddyken2305Eliminated

So, using the approximate pattern of transfers we observed this week (DP to FF; G to Nei to FG, but with a large amount of random scatter), here's how things unfold.

Hypothetical East, 31 June 2007. Quota - 10,000. Counts 2-5
PartyCandidateTransferVote 2TransferVote 3TransferVote 4TransferVote 5
FFH. Morrison+6048604+338637+2478884+1379021
FFW. Budgen+6118455+728527+5329059+1289187
FFM. Marks+6118358+378395+4448839+1068945
FGP. Beaufort+925878+5386416+4506866+806946
FGF. Storm+145526+5496075+8576932+146946
FGH. Cane+725572+4766048+2636311+656376
NeiT. Blair+414770+9935763+4626225+484811073
NeiG. Brown+534677+9345611+1225733-57330
SFS. M. Tex+694429+984527-45270
GI. Chagall+1383730-37300
DPC. Eddyken-23050

Though he came seventh on first preferences, transfers from other parties have promoted Blair to be the first person elected. We'll play out the count:

Hypothetical East, 31 June 2007. Quota - 10,000. Counts 6-7
PartyCandidateTransferVote 6TransferVote 7
FFH. Morrison+219158+1079265
FFW. Budgen+109315+409355
FFM. Marks+439051+109061
FGP. Beaufort+3147026+29389964
FGF. Storm+2836960+29119871
FGH. Cane+2776441-64410
NeiT. Blair-107310000010000

At this point the count concludes, with Morrison, Budgen, Beaufort, and Storm elected without receiving a quota; the distribution of Marks (and surpluses) will force the other candidates over quota.

So, should parties field more candidates still? Perhaps not; let's see what happens if FF gets cocky and campaigns badly - the party fields a full slate of candidates, receive only 35% of first preferences, and find their preferred partners the DPs fall right away:

Hypothetical East, 31 June 2007. Quota - 10,000. Count 1
PartyCandidateVote
FGP. Beaufort6145
FGF. Storm5945
FGH. Cane5856
SFS. M. Tex5034
NeiT. Blair5024
NeiG. Brown4902
FFH. Morrison4706
FFW. Budgen4739
FFM. Marks4547
FFN. Spencer4427
GI. Chagall4399
FFJ. Sainsbury4268
DPC. Eddyken107

Between them, the FF candidates are down to about two-and-a-quarter quotas. Rather than put up even more long tables, we'll skip to what happens after the minor candidates and first FF candidate have been eliminated.

Hypothetical East, 31 June 2007. Quota - 10,000. Count 4
PartyCandidateVote
FGP. Beaufort7487
FGF. Storm7292
FGH. Cane7246
SFS. M. Texeliminated 3
NeiT. Blair6374
NeiG. Brown6282
FFH. Morrison5735
FFW. Budgen5707
FFM. Marks5580
FFN. Spencer5435
GI. Chagalleliminated 2
FFJ. Sainsburyeliminated 1
DPC. Eddykeneliminated 1

Spencer falls out, lifting the three remaining FF candidates above the Neighbours, then Brown's elimination elects Blair.

Hypothetical East, 31 June 2007. Quota - 10,000. Count 6
PartyCandidateVote
FGP. Beaufort8655
FGF. Storm7914
FGH. Cane7938
SFS. M. Texeliminated 3
NeiT. Blair11801 - ELECTED
NeiG. Browneliminated 5
FFH. Morrison7247
FFW. Budgen7431
FFM. Marks6712
FFN. Spencereliminated 4
GI. Chagalleliminated 2
FFJ. Sainsburyeliminated 1
DPC. Eddykeneliminated 1

Look at the remaining FF votes. They've dropped from two-and-a-quarter quotas to barely two quotas. Blair's surplus (in reality, the third preference of Brown's transfers) still goes almost entirely to FG, third FF candidate Marks is eliminated, and here's the final score:

Hypothetical East, 31 June 2007. Quota - 10,000. Count 8
PartyCandidateVote
NeiT. BlairELECTED count 6
FGP. Beaufort9824 - ELECTED
FGF. Storm9804 - ELECTED
FFW. Budgen9631 - ELECTED
FGH. Cane9563 - ELECTED
FFH. Morrison9546
FFM. Markseliminated 7
NeiG. Browneliminated 5
FFN. Spencereliminated 4
SFS. M. Texeliminated 3
GI. Chagalleliminated 2
FFJ. Sainsburyeliminated 1
DPC. Eddykeneliminated 1

FF only has one person elected, the fifth seat has gone to FG. Why has this happened? It's simple - transfers are never 100% effective. Voters will not always follow party lines exactly - in the example above, some voters may have taken a shine to candidates Marks and Spencer, but think that Morrison is a cheapskate unworthy of their vote. They'd rather see someone - anyone - else elected ahead of him.

The strategy is to field at least as many candidates as seats you're certain of winning, but no more than you think you could possibly win. Generally, these numbers will either be identical, or separated by just one candidate. Fielding too few candidates is a sign of little confidence; fielding too many allows transfers to erode your support.

In the example cited by Dr. V earlier, Labour fielded two candidates, and four other parties put up just one. Three candidates were to be elected. We suspect that at least one of the one-candidate parties should have put up a second candidate, but it's difficult to predict which.

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